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useTimeoutFn

超时将会执行回调函数

python
def callback():
    print("timeout")

timeout = useTimeoutFn(1, callback)
timeout.start()
# do something need 2 seconds
timeout.stop()
python
def callback():
    print("timeout")

# 无需`start`立即生效
timeout = useTimeoutFn(1, callback, immediate = True)
# timeout.start()
# do something need 2 seconds

useTimeout

超时

python
timeout = useTimeout(0.1)

Released under the MIT License.